A man 40 m from the foot of a tower observes the angle of elevation of the tower to be 30º. Determine the height of the tower.
Tan 30 = \(\frac{h}{40}\)
\(\frac{1}{\sqrt{3}}=\frac{h}{40}\)
h\(\sqrt{3}\) = 40
h = \(\frac{40}{\sqrt{3}}\)
h = \(\frac{40}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}\)
h = \(\frac{40\sqrt{3}}{3}\)
There is an explanation video available below.
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