The solution of the quadratic inequality (x\(^2\) + x - 12) ≥ 0 is
(x\(^2\) + x - 12) ≥ 0 (x + 4)(x - 3) ≥ 0 Either x + 4 ≥ 0 implies x ≥ - 4 Or x - 3 ≥ 0 implies x ≥ 3 ∴ x ≥ 3 or x \(\leq\) -4
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