The sum of the first n positive integers is
Let the positive integers be 1, 2, ,3, 4, .....n ∴ a = 1, d = 1 and n = n Sn = n/2(2a + (n-1)d) = n/2 (2 + n – 1) = 1/2n(n + 1)
There is an explanation video available below.
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