Solve the inequalities for which \(\frac{x+4}{3}-\frac{x-3}{2} < 4\)
\(\frac{x+4}{3}-\frac{x-3}{2}\) < 4 \(\frac{(2(x+4))-(3(x-3))}{6}\) < 4 2(x+4) – 3(x-3) < 4 x 6 2x + 8 – 3x+9 < 24 -x + 17 < 24 -x < 24 – 17 -x < 7 x > -7
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