In the diagram above, POQ is a diameter of the circle PQRS. If ∠PSR = 145°, find x°
∠PSQ = 90° (∠ in semi circle) ∠PSQ + ∠QSR = 145° 90 + ∠QSR = 145 ∠QSR = 145 - 90 ∠QSR = 55° BUt x° = ∠QSR (∠s in the same segment) ∴x° = 55°
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