Evaluate \(\int_{-4}^0(1 - 2x)dx\)
\(\int_{-4}^0(1 - 2x)\)dx = \([x - x^2]_{-4}^0\) = (0 - 0 + C) - (-4 - (-4)\(^2\) + C) = C - ( - 4 - 16 +C ) = C - ( - 20 + C) = C + 20 - C = 20
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