Find the variance of 2x, 2x-1 and 2x+1
\(\sum x = 6x\) \(\sum(x-\bar{x})^2\) = 2 \(\bar{x} = \frac{\sum x}{n}\) = \(\frac{6x}{3}\) = 2x Variance = \(\frac{\sum(x-\bar{x})^2}{n}\) = \(\frac{2}{3}\)
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