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Find the derivative of y = sin(2x\(^3\) + 3x - 4)

Mathematics
JAMB 2005

Find the derivative of y = sin(2x\(^3\) + 3x - 4)

  • A. cos (2x3 + 3x - 4)
  • B. -cos (2x3 + 3x - 4)
  • C. (6x2 + 3) cos (2x3 + 3x - 4)
  • D. -(6x2 + 3) cos (2x3 + 3x - 4)
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Correct Answer: Option C
Explanation

y = sin (2x\(^3\) + 3x - 4)
let u = 2x\(^3\) + 3x - 4
∴du/dx = 6x\(^2\)
y = sin u
dy/du = cos u
dy/dx = du/dx * dy/du
∴dy/dx = (6x\(^2\) + 3) cos u
= (6x\(^2\) + 3)cos(2x\(^3\) + 3x - 4)


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Project Topics and Materials, Post-UTME past questions - Download now or upload yours to get paid
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NECO June/July 2024 - Get offline past questions & answers - Download objective & theory, all in one app 48789
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