If y = (1 - 2x)\(^3\), find the value of dy/dx at x = -1

Peter9695

2 years ago

To find the derivative of y with respect to x, we'll apply the chain rule:

y = (1 - 3x)^2

dy/dx = d(1 - 3x)^2/dx
= 2(1 - 3x) * d(1 - 3x)/dx
= 2(1 - 3x) * (-3)
= -6(1 - 3x)

Now, evaluate the derivative at x = -1:

dy/dx at x = -1 = -6(1 - 3(-1))
= -6(1 + 3)
= -6(4)
= -24

So, the value of dy/dx at x = -1 is -24.