Mathematics
JAMB 2005
If the 7th term of an AP is twice the third term and the sum of the first four terms is 42, find the common difference.
Correct Answer: Option B
Explanation
U
7 = a + (7 - 1)d
= a + 6d
U
3 = a + (3 - 1)d
= a + 2d
But U
7 = 2(U
3)
∴a + 6d = 2(a + 2d)
a + 6d = 2a + 4d
2a - a + 4d - 6d = 0
a - 2d = 0 → eqn1
Sn =
n/
2 (2a + (n - 1)d)
42 =
4/
2 (2a + (4 - 1)d)
42 = 2(2a + 3d)
21 = 2a + 3d → eqn2
eqn1 * eqn2 0 = 2a - 4d
21 = 7d
∴d =
21/
7
d = 3
There is an explanation video available below.
Report an Error
Ask A Question
Download App
Explanation Video
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}