Correct Answer: Option B

Explanation

\(\frac{81^{\frac{3}{4}}-27^{\frac{1}{3}}}{3 \times 2^3} = \frac{(3^{3-\frac{3}{4}}-3^{3-\frac{3}{4}})}{3\times 2^3}\\=\frac{3^3 - 3}{3 \times 8}\\=\frac{27-3}{24}\\=\frac{24}{24}\\=1\)

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