Evaluate \(\frac{(81^{\frac{3}{4}}-27^{\frac{1}{3}})}{3 \times 2^3}\)
\(\frac{81^{\frac{3}{4}}-27^{\frac{1}{3}}}{3 \times 2^3}\)
= \(\frac{(3^{3-\frac{3}{4}}-3^{3-\frac{3}{4}})}{3\times 2^3}\)
= \(\frac{3^3 - 3}{3 \times 8}\)
= \(\frac{27-3}{24}\\=\frac{24}{24}\) =1
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