If the interest on N150.00 for 2\(\frac{1}{2}\) years is N4.50, find the interest on N250.00 for 6 months at the same rate
To find the interest on \( N250.00 \) for \( 6 \) months at the same rate, we follow these steps:
Calculate the Interest Rate
Given: P = N150.00, T = 2\(\frac{1}{2}\) years and I = N4.50
Using the formula for simple interest:
\(I = P \times r \times T\)
Rearranging to find the interest rate \( r \):
\(r = \frac{I}{P \times T}\)
Substituting the values:
\(r = \frac{4.50}{150 \times 2.5}\)
Calculating \( P \times T \):
\(P \times T = 150 \times 2.5 = 375\)
Now, substituting back to find \( r \):
\(r = \frac{4.50}{375} = 0.012\)
Calculate the Interest for N250.00 \) for 6 Months
We need to calculate the interest for: P = N250.00, T = 6 months = 0.5yrs, r = 0.012
Using the interest formula again:
\(I = P \times r \times T\)
Substituting the values:
\(I = 250 \times 0.012 \times 0.5\)
\(I = 250 \times 0.012 = 3\)
Then: \(I = 3 \times 0.5 = 1.50\)
The interest on \( N250.00 \) for \( 6 \) months at the same rate is N1.5
There is an explanation video available below.
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