If the interest on N150.00 for 2\(\frac{1}{2}\) years is N4.50, find the interest on N250.00 for 6 months at the same rate
N1.50
N7.50
N15.00
N18.00
Explanation
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The answer is correct you just have to convert the 2.5 yrs to 30 months,, since the same rate applies to both interest in the question.

here is the solutionLet's break it down step by step:
Given Information
1. *Principal (P)*: ₦150
2. *Time (T)*: 2.5 years
3. *Interest (I)*: ₦4.50
Calculate Interest Rate (R)
We can use the formula:
I = (P × R × T) / 100
Rearranging to solve for R:
R = (I × 100) / (P × T)
Plugging in the values:
R = (₦4.50 × 100) / (₦150 × 2.5)
= 450 / 375
= 1.2%
Calculate Interest for New Scenario
1. *New Principal (P)*: ₦250
2. *New Time (T)*: 6 months = 0.5 years
Using the same interest rate (R = 1.2%):
I = (P × R × T) / 100
= (₦250 × 1.2 × 0.5) / 100
= ₦1.50
So, the interest on ₦250 for 6 months at the same rate would be ₦1.50.

My school please make the maths hard please I want to be seeing geometry or world problem wtf is this

