\(\frac{1}{\sqrt{3}+2}\)
= \(\frac{1}{\sqrt{3}+2}\times \frac{\sqrt{3} - 2}{\sqrt{3} - 2}\)
= \(\frac{\sqrt{3}-2}{(\sqrt{3})^{2} -2^{2}}\)
= \(\frac{\sqrt{3}-2}{3-4}\)
= \(\frac{\sqrt{3}-2}{1}\) = -\(\sqrt{3}+2\)
= 2- \(\sqrt{3}\)
There is an explanation video available below.
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