Given that \(\sqrt[3]{{4}}\)\(^{2x}\) = 16, find the value of x

mmeso

1 year ago

to remove the cube root you multiply both sides by 3 (raised to the power of 3)
4²X = 16³
4²X = 4 ² × ³
4²X = 4 ⁶
the base is the same so you take the index
2x = 6
x= 6/2
x= 3

victorogundepo008

5 years ago

thats it

Anonymous1005035

6 years ago

Please can someone explain to me the solving above?