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Factorize completely ac - 2bc - a\(^2\) + 4b\(^2\)

Mathematics
JAMB 2004

Factorize completely ac - 2bc - a\(^2\) + 4b\(^2\)

  • A. (a - 2b)(c - a - 2b)
  • B. (a - 2b)(c + a +2b)
  • C. (a - 2b)(c - a + 2b)
  • D. (a - 2b)(c + a - 2b)
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Correct Answer: Option A
Explanation

ac - 2bc - a\(^2\) + 4b\(^2\)
ac - 2bc - (a\(^2\) - 4b\(^2\))
ac - 2bc - (a\(^2\) -(2b)\(^2\))
c(a - 2b) - {(a - 2b)(a + 2b)}
(a - 2b)(c - (a + 2b))
(a - 2b)(c - a - 2b)

There is an explanation video available below.


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Explanation Video

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