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In how many ways can 2 students be selected from a group of 5 students...

Mathematics
JAMB 2004

In how many ways can 2 students be selected from a group of 5 students in a debating competition?

  • A. 25 ways
  • B. 10 ways
  • C. 15 ways
  • D. 20 ways
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Correct Answer: Option B
Explanation

The number of ways of selecting the debtors = \(^5C_2\) ways

\(^5C_2\) = \(\frac{5!}{(5 - 2)!2!}\)

= \(\frac{5 . 4 . 3!}{(3!)2!}\) = \(\frac{5. 4}{2. 1}\) = 10ways

(3!s cancels ou)

 

There is an explanation video available below.


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