Find the derivatives of the function y = 2x\(^2\)(2x - 1) at the point x = -1?
18
16
-4
-6
Explanation
Video Explanation
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For those Confused Let me Simplify It.
So the Question is:
Find the derivatives of the function y = 2x2
(2x - 1) at the point x = -1?
A. 18
B. 16
C. -4
D. -6
Where the Answer is 16. Let me Explain Why.
First We are to Differentiate Y= 2x^2 (2x-1) at point x= -1, Meaning where x is -1, simply means X=-1.
before we start differentiating we Open the bracket so (2x^2) X (2x) + (2x^2) X (-1)
then we get 4x^3 - 2x^2
So we defferentiate the both sides where;
Y differentiated is dy/dx
And 4x^3 = 12x^2 and 2x^2 = 4x
So we have :
dy/dx = 12x^2 - 4x
so we substitute x= -1 inside so we have
dy/dx = 12(-1)^2 - 4 (-1)
which is :
dy/dx = 12 + 4 = 16
Following the rules of Calculus, the question is supposed to be solved using product rule. The answer is -6.
please can the video about the solving be done, please I don't quite understand.
