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A predator moves in a circle of radius √2 centre (0,0), while a prey moves...

Mathematics
JAMB 2000

A predator moves in a circle of radius √2 centre (0,0), while a prey moves along the line y = x. If 0 \(\leq\) x \(\leq\) 2, at which point(s) will they meet?
  • A. (1,1) only
  • B. (1,1) and (1,2)
  • C. (0,0) and (1,1)
  • D. (√2,√2) only
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Correct Answer: Option A
Explanation
x2 + y2 = (√2)2
x2 + y2 = 2
but y = x

Thus; x2 + x2 = 2
2x2 = 2
x2 = + or - 1

But x2 + y2 = 2
12 + y2 = 2
1 + y2 = 2
y2 = 2 - 1
y2 = 1
y = + or - 1

Thus point (x,y) = (1,1) only.

There is an explanation video available below.


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Explanation Video

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JAMB CBT Mobile App 2025 - Free Download
JAMB CBT 2025 - Candidates, Schools, Centres, Resellers - Get Ready!
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 127076
JAMB CBT Software 2025 - Free Download
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 127076
JAMB CBT 2025 - Candidates, Schools, Centres, Resellers - Get Ready!
JAMB CBT Software 2025 - Free Download
JAMB CBT Mobile App 2025 - Free Download