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3y = 4x - 1 and Ky = x + 3 are equations of two...

Mathematics
JAMB 2000

3y = 4x - 1 and Ky = x + 3 are equations of two straight lines. If the two lines are perpendicular to each other, find K.

  • A. -\(\frac{4}{3}\)
  • B. -\(\frac{3}{4}\)
  • C. \(\frac{3}{4}\)
  • D. \(\frac{4}{3}\)
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Correct Answer: Option A
Explanation

Grad of 3y = 4x - 1
y = \(\frac{4x}{3}\) - \(\frac{1}{3}\)
Grad = \(\frac{4}{3}\)

Grad of Ky = x + 3
y = \(\frac{\text{x}}{\text{k}}\) + \(\frac{3}{4}\)
Grad = \(\frac{1}{\text{k}}\)

Since the two lines are perpendicular,
\(\frac{1}{\text{k}}\) = -\(\frac{3}{4}\)
-3k = 4
k = -\(\frac{4}{3}\)

There is an explanation video available below.


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Explanation Video

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