3y = 4x - 1 and Ky = x + 3 are equations of two straight lines. If the two lines are perpendicular to each other, find K.
a
-\(\frac{4}{3}\)
b
-\(\frac{3}{4}\)
c
\(\frac{3}{4}\)
d
\(\frac{4}{3}\)
Explanation
Correct Option
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Eugene1097
1 year ago
I no belive this one
when two lines are perpendicular product of their gradient is =-1
