A bag contains 5 blacks balls and 3 red balls. Two balls are picked at random without replacement. What is the probability that a black and red balls are picked?
a
\(\frac{15}{28}\)
b
\(\frac{13}{28}\)
c
\(\frac{5}{14}\)
d
\(\frac{3}{14}\)
Explanation
Correct Option
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IfechuksJoizzy
12 years ago
without replacement here, means when one is picked, it cant be replaced. the answer would be, BR.(without being replaced) + RB(without being replaced)...........the balls are 5+3=8........... so (5/8 * 3/7) + (3/8 * 5/7)......... we have 15/56 + 15/56 = 15/28: thats the answer.. Thank you.
