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Find the mean of the distribution above value 0 1 2 3 4 Frequency 1...

Mathematics
JAMB 2003

Find the mean of the distribution above

value 0 1 2 3 4
Frequency 1 2 2 1 9

 

  • A. 1
  • B. 2
  • C. 3
  • D. 4
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Correct Answer: Option C
Explanation

Mean = \(\frac{(0 \times 1) + (1 \times 2) + (2 \times 2) + (3 \times 1) + (4 \times 9)}{1 + 2 + 2 + 1 + 9}\)

= \(\frac{(0 + 2 + 4 + 3 + 36)}{15}\)

= \(\frac{45}{15}\) =3

There is an explanation video available below.


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Explanation Video

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