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The sum of the first n terms of an arithmetic progression is 252. If the...

Mathematics
JAMB 2003

The sum of the first n terms of an arithmetic progression is 252. If the first term is -16 and the last term is 72, find the number of terms in the series

  • A. 6
  • B. 7
  • C. 8
  • D. 9
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Correct Answer: Option D
Explanation

Using: \(S_n = \frac{n}{2} (a + l)\)

where:- \(S_n\) is the sum of the first \(n\) terms, \(a\) is the first term, \(l\) is the last term.

Given: \(S_n = 252\), a = -16, l = 72

Step 1: Substitute the Known Values

Substituting the values into the sum formula:

\(252 = \frac{n}{2} (-16 + 72)\)

\(252 = \frac{n}{2} \cdot 56\)

\(504 = n \cdot 56\)

Now, divide both sides by 56:

n = \(\frac{504}{56}\) = 9

Thus, the number of terms in the series is: 9

There is an explanation video available below.


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Explanation Video

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