In the diagram above , XZ is the diameter of the circle XZW, with center O and radius 15/2 cm. If XY = 12 cm, find the area of the triangle XYZ

Ann_e

1 year ago

We’re given:
• XZ is the diameter of the circle.
• O is the center, so radius = 15/2 cm, hence diameter XZ = 15 cm.
• XY = 12 cm
• Triangle XYZ is inside the circle, with angle ∠Y = 90° (because angle subtended by a diameter in a circle is a right angle).
• We’re to find the area of triangle XYZ.

Step 1: Use right-angle triangle area formula

Since ∠Y = 90°, triangle XYZ is a right-angled triangle at Y.

So the area is:
area=1/2bh

Here:
• Base = XY = 12 cm
• Hypotenuse = XZ = 15 cm
• Use Pythagoras to find YZ (the other leg):

XY^2 + YZ^2 =XZ^2
12^2 + YZ^2 =15^2
225-144=YZ^2
YZ=9cm

Step 2: Find the area
area=1/2*12*9
=54cm3
Final Answer:
54cm3

CHIBIKE007

9 years ago

I THINK YOU GUYS NEED TO WORK ON YOUR ANSWER BECAUSE SOME ARE NOT CORRET CHECK THE MATHS THANKS FOR PROVIDING A PLATFORM FOR US ASPIRANT

kjamiu

9 years ago

The question is wrongly composed:

the diameter should be 24 while the hypothesis should be 15 as solved in other to get that answer

REF: 41

Tlase

1 year ago

There is no explanation, its just blank.

Craig Duffy

9 years ago

hahahahahaha...lollzzz, wah d f**k re u guys solving????? the only approach we can use is Hero's formulae.. if it were an isosceles triangle, eh henh, the formulae used abv is OK.

Craig Duffy

9 years ago

like ah was saying..haha, d answer u guys got is correct BT how it was solved is wrong .



angle in a semi equal 90°.

Craig Duffy

9 years ago

angle in a semi equal 90°.

Chimemeria

9 years ago

my school...the solution is totally wrong