A number is selected at random from 0 to 20. What is the probability that the number is odd?
The numbers from 0 to 20 inclusive are:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20.
Total numbers = 21
Odd prime numbers in this range:
Primes must be greater than 1 and have no divisors other than 1 and themselves.
Odd primes (exclude 2, which is even):
3, 5, 7, 11, 13, 17, 19
→ There are 7 odd prime numbers.
3. Probability = \(\frac{\text{Number of favourable outcomes}}{\text{Total outcomes}}\)
= \(\dfrac{7}{21} = \dfrac{1}{3}\)
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}