If y ∝ \(\frac{1}{x^2}\) and x = 3, when y = 4, find y when x = 2
y ∝ \(\frac{1}{x^2}\)
y = \(\frac{\text{k}}{x^2}\)
When x = 3, y = 4.
4 = \(\frac{\text{k}}{9}\)
k = 36.
When x = 2,
y = \(\frac{36}{4}\) = 9
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