Correct Answer: Option B

Explanation

log\(_2a\) = log\(_84\)

Let  log\(_84\) = y

Then 4 = 8\(^y\)

2\(^2\) = 2\(^{3y}\)

2 = 3y

y = \(\frac{2}{3}\)

log\(_2a\) = log\(_84\) = \(\frac{2}{3}\)

log\(_2a\) =  \(\frac{2}{3}\)

a = 2\(^{\frac{2}{3}}\)

(Note: The logarithm was converted to index form.)

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