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Solve for y in \(\sqrt{75}\) - \(\sqrt{12}\) + \(\sqrt{27}\) = y\(\sqrt{3}\)

Mathematics
JAMB 2025

Solve for y in \(\sqrt{75}\) - \(\sqrt{12}\) + \(\sqrt{27}\) = y\(\sqrt{3}\)

  • A. \(4\sqrt{3}\)
  • B. \(5\sqrt{3}\)
  • C. \(3\sqrt{3}\)
  • D. \(6\sqrt{3}\)
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Correct Answer: Option D
Explanation

\(\sqrt{75} - \sqrt{12} + \sqrt{27} = y\sqrt{3}\)

Simplify each term:

- \(\sqrt{75} = \sqrt{25 \times 3} = 5\sqrt{3}\)
- \(\sqrt{12} = \sqrt{4 \times 3} = 2\sqrt{3}\)
- \(\sqrt{27} = \sqrt{9 \times 3} = 3\sqrt{3}\)

Substitute: \(5\sqrt{3} - 2\sqrt{3} + 3\sqrt{3} = y\sqrt{3}\)

Combine like terms: \((5 - 2 + 3)\sqrt{3} = y\sqrt{3}\)

\(6\sqrt{3} = y\sqrt{3}\)

Thus, y = 6

There is an explanation video available below.


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Explanation Video

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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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