Solve x\(^2\) + 3x - 4 ≤ 0
To solve \(x^2 + 3x - 4 \leq 0\):
Factorize: \((x + 4)(x - 1) \leq 0\)
Roots: \(x = -4\), \(x = 1\)
Solution: \(-4 \leq x \leq 1\) .
There is an explanation video available below.
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