Find the sum of the entries in the inverse of \(\begin{bmatrix} 1 & 2 \\ 3 & 5 \end{bmatrix}\)

Praokp25

3 months ago

in your description you said
1/determinant(.)sum of the adjoints right and I assume the (.) sign means multiplication
so 1/-1×-1(the answer you got when you summed up the adjoint)
-1×-1= 1so your answer should be 1

Sensei

1 month ago

correct.