To divide \(6x^2 - 13x + 5\) by \(2x - 1\):
\(\begin{array}{r|l}
3x - 5 & \\
\hline
2x - 1 & 6x^2 - 13x + 5 \\
& -(6x^2 - 3x) \\
\hline
& -10x + 5 \\
& -(-10x + 5) \\
\hline
& 0 \\
\end{array}\)
Thus, the quotient is: 3x - 5
There is an explanation video available below.
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