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Divide 6x\(^2\) - 13x + 5 by 2x - 1 

Mathematics
JAMB 2005

Divide 6x\(^2\) - 13x + 5 by 2x - 1 

  • A. 3x + 5
  • B. 3x - 5
  • C. 5x - 3
  • D. 5x + 3
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Correct Answer: Option B
Explanation

To divide \(6x^2 - 13x + 5\) by \(2x - 1\):

\(\begin{array}{r|l}
           3x - 5 &  \\
\hline
2x - 1 & 6x^2 - 13x + 5 \\
           & -(6x^2 - 3x) \\
\hline
           & -10x + 5 \\
           & -(-10x + 5) \\
\hline
           & 0 \\
\end{array}\)

Thus, the quotient is: 3x - 5

There is an explanation video available below.


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Explanation Video

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