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2024 WAEC Mathematics Theory (a) Find the equation of the line that passes through the origin and the point...

Mathematics
WAEC 2024

(a) Find the equation of the line that passes through the origin and the point of intersection of the lines \( x + 2y = 7 \) and \( x - y = 4 \). (b) The ratio of an interior angle to an exterior angle of a regular polygon is 4: 1. Find the: (i) number of sides; (ii) value of the exterior angle; and (iii) sum of the interior angles of the polygon.

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Explanation

(a) Solving the eqns of the two lines simultaneously:

x + 2y = 7  - - -- - - - - - -(i)

x - y = 4 - - - - - - - - - - - -(ii)

subtract eqn (ii) from (i)

x - x + 2y - (- y) = 7 - 4

3y = 3

y = 1

put y = 1 into eqn (ii)

x - 1 = 4

x = 4 + 1 = 5

The point of intersection of lines is (5, 1)

⇒ If the line passes through Origin (0, 0) and (5, 1)

Using: \(\frac{y_2 - y_1}{x_2 - x_1} = \frac{y - y_1}{x  - x_1}\)

\(\frac{1 - 0}{5 - 0} = \frac{y - 0}{x  - 0}\)

\(\frac{1}{5} = \frac{\text{y}}{\text{x}}\)

Therefore, the equation of the line = x - 5y = 0

(b) Given that the ratio of the interior angle to the exterior angle of a regular polygon = 4: 1

Thus, I = 4E

But, the sum of the interior angles and the exterior angles of a regular polygon = 180

i.e. I + E = 180

      4E + E = 180

5E = 180

E = \(\frac{180}{5}\) = 36º

Since, I = 4E = 4 x 36 = 144º

(ii) value of the exterior angle = 36º

(i) Number of sides of the polygon = \(\frac{360}{\text{n}}\) = E, n =  \(\frac{360}{36}\) = 10 (since E = 36º)

(iii) Sum of the interior angles of the polygon. = (n - 2)180 = (10 - 2)180 = 8 x 180 = 1,440.

 

 

 


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