In the diagram, ABCD is a circle O. The quadratic OBCD is a rhombus such that \(\angle\)ADO = \(\angle\)OBA = y and \(\angle\)BAD = t. Find;

(a) the value of t;

(b) the value of y;

(c) \(\angle\)ADC.

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Discussions (4)

chimonk
1 year ago

in answering questions 4c , why did you use angle OBD twice instead of angle OBD+ ODB+ BOD?

olami3243
2 months ago

how did you know that BDC was 30°

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