Correct Answer: Option C

Explanation

\(\frac{y + 2}{8y^2 - 10y + 3}\) not defined when the denominator is equal to zero

8y\(^2\) - 10y + 3 = 0 using factorization method

8y\(^2\) - 6y - 4y + 3 = 0

2y(4y - 3) - 1(4y - 3) = 0

(4y - 3)(2y - 1) = 0

4y - 3 = 0 or 2y - 1 = 0

Hence, y = \(\frac{3}{4}\) or \(\frac{1}{2}\)

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