The probability that Amaka will pass an examination is \(\frac{3}{7}\) and that Bala will pass is \(\frac{4}{9}\). Find the probability that both will pass the examination.
Pr(Amaka passes) = \(\frac{3}{7}\), Pr(Bala passes) = \(\frac{4}{9}\).
Pr(both Amaka and Bala pass the exam) = \(\frac{3}{7}\) x \(\frac{4}{9}\) = \(\frac{4}{21}\).
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