In the diagram above, JKL is a tangent to the circle GHIK at K. Find the value of the angle marked x
\(\angle\)KGL = 87º (exterior angle of a cyclic quadrilateral)
\(\angle\)KGL + \(\angle\)GLK + \(\angle\)LKG = 180º
87º + x + 38º = 180º
x = 180 - 87 - 38 = 55º
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}