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If log\(_3^{2x - 1}\) = 5, find the value of x

Mathematics
WAEC 2024

If log\(_3^{2x - 1}\) = 5, find the value of x

  • A. 8
  • B. 16
  • C. 64
  • D. 122
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Correct Answer: Option D
Explanation

log\(_3^{2x - 1}\) = 5 in index form becomes  3\(^5\) = 2x - 1

2x - 1 = 243

2x = 243 + 1 = 244

x = \(\frac{244}{2}\) = 122


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