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(\(\sqrt{a} +\sqrt{8a})^2\) = 54 + b\(\sqrt{2}\), a and b are positive integers. Find the value...

Mathematics
JAMB 2024

(\(\sqrt{a} +\sqrt{8a})^2\) = 54 + b\(\sqrt{2}\), a and b are positive integers. Find the value of a and the value of b.

  • A. a = 24, b = 6
  • B. a = 6, b = 2
  • C. a = 6, b = 24
  • D. a = 2, b = 6
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Correct Answer: Option C
Explanation

(\(\sqrt{a} +\sqrt{8a})^2\) =  54 + b\(\sqrt{2}\)

(\(\sqrt{a} + \sqrt{8a}\))(\(\sqrt{a} + \sqrt{8a}\))

a + 4a\(\sqrt{2} + 8a = 54 + b\sqrt{2}\)

9a + 4a\(\sqrt{2}\) = 54 + b\(\sqrt{2}\)

comparing both sides

9a = 54, so that a = 6

4a = b

b = 4 x 6 = 24.

There is an explanation video available below.


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Explanation Video

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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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