Make q the subject of the relation t = \(\sqrt{(\frac{pq}{r} - r^2q)}\)
a
q = \(\frac{rt^2}{p - r^3}\)
b
q = \(\frac{p - r^3}{rt^2}\)
c
q = \(\frac{t^2}{p - r^3}\)
d
q = \(\frac{rt}{p - r^3}\)
Explanation
Correct Option
aVideo Explanation
Post your Contribution
Share:
