Correct Answer: Option B

Explanation

Given \(\tan \theta = \frac{8}{15}\)

\(\sin \theta = \frac{8}{17}, \quad \cos \theta = \frac{15}{17}\) from pythagora's theorem.

To find  \(\frac{\sin \theta - \cos \theta}{\sin^2 \theta - \sin \theta}\)

Numerator  → \(\sin \theta - \cos \theta = \frac{8}{17} - \frac{15}{17} = \frac{-7}{17}\)

Denominator → \(\sin^2 \theta = \left(\frac{8}{17}\right)^2 = \frac{64}{289}, \quad \sin^2 \theta - \sin \theta = \frac{64}{289} - \frac{136}{289} = \frac{-72}{289}\)

\(\frac{\frac{-7}{17}}{\frac{-72}{289}} = \frac{7 \times 289}{17 \times 72} = \frac{119}{72}\)

There is an explanation video available below.

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