Find x if \(\frac{16^{2 + x}}{4} = 64^x\)
\(\frac{16^{2 + x}}{4} = 64^x\)
16\(^{2 + x} = 4 \times 64^x\)
4\(^{2(2 + x)} = 4^1 \times 4^{3(x)}\)
(Equate coefficients since the bases are the same)
2(2 + x) = 1 + 3x
4 + 2x = 1 + 3x
2x - 3x = 1 - 4
-x = -3
x = 3.
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