PQR is a triangle such that |PQ| = |QR| = 8cm and QPR = 60º. Find the area of \(\angle\) PQR

a

16\(\sqrt{3}cm^2\)

b

16\(\sqrt{2}cm^2\)

c

8\(\sqrt{3}cm^2\)

d

16\(\sqrt{2}cm^2\)

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a

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Odemosad
1 year ago

Using Area of ∆ = 1/2xaxbxsintheta

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