make x the subject of the relation \(y = \frac{ax^3 - b}{3z}\)
a
x = \(\sqrt[3] \frac{ax^3 - b}{3z}\)
b
x = \(\sqrt[3] \frac{3yz - b}{a}\)
c
x = \(\sqrt[3] \frac{3yz + b}{a}\)
d
x = \(\sqrt[3] \frac{3yzb}{a}\)
Explanation
Correct Option
cVideo Explanation
No video available
Post your Contribution
Share:
Discussions (0)
No comments yet
Be the first to comment
