In the diagram, O is the center of the circle QRS and ∠SQR = 28°. Find ∠ORS.
\(56^0\)
\(28^0\)
\(76^0\)
\(62^0\)
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it is hard ooo
NBL
ceoofwahala
20th June, 2026
ASSAAS
infinitehoaxx
21st May, 2026