The second term of a geometric series is \(^{-2}/_3\) and its sum to infinity is \(^3/_2\). Find its common ratio.
a
\(^{-1}/_3\)
b
2
c
\(^{4}/_3\)
d
\(^{2}/_9\)
Explanation
Correct Option
aVideo Explanation
Post your Contribution
Share:
Discussions (6)
Phoenixboyz
1 year ago
There is an error in the solution. After substitution, the +4 was added to both sides, but yet it remained negative
= 3(3r - 3r2) = -4
= 9r - 9r2 = -4 
, then
= 9r2 - 9r - 4 = 0
