Correct Answer: Option B

Explanation

tan θ = \(\frac {opp}{adj} = \frac {RQ}{QP} = \frac {6}{8}\)

tan θ = 0.75

θ = tan\(^{-1} (0.75) = 36.87^o\)

∴ The bearing of R from P = 360\(^o\) - 36.87\(^o\) = 323\(^o\) (to the nearest degree)

There is an explanation video available below.

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