Given that y =(\(\frac{pr}{m} - p^2r\))\(^{\frac{-3}{2}}\)
(a) make r the subject;
(b) find the value of r when y = -8, m = 1 and p = 3.
(a) y =(\(\frac{pr}{m} - p^2r\))\(^{\frac{-3}{2}}\)
y\(^{\frac{-2}{3}}\) =(\(\frac{pr}{m} - p^r2\))
my\(^{\frac{-2}{3}}\) =(\(\frac{pr- p^r2m}{m}\))
my\(^{\frac{-2}{3}}\) = pr - p\(^2\)rm
my\(^{\frac{-2}{3}}\) = r(p - p\(^2\)m)
r = (\(\frac{my^{-2/3}}{m - p^2m}\))
(b) r = (\(\frac{1-8^{-2/3}}{3 - 3^2 * 1}\))
= \(\frac{1}{4}\) ÷ -6
= - \(\frac{1}{-6}\)
= - \(\frac{1}{24}\)
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